Optimal. Leaf size=467 \[ \frac {e x \sqrt {a+b x^2+c x^4} \left (-3 c e (3 a e+10 b d)+8 b^2 e^2+45 c^2 d^2\right )}{15 c^{5/2} \left (\sqrt {a}+\sqrt {c} x^2\right )}-\frac {\sqrt [4]{a} e \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+b x^2+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} \left (-3 c e (3 a e+10 b d)+8 b^2 e^2+45 c^2 d^2\right ) E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{4} \left (2-\frac {b}{\sqrt {a} \sqrt {c}}\right )\right )}{15 c^{11/4} \sqrt {a+b x^2+c x^4}}+\frac {\sqrt [4]{a} \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+b x^2+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} \left (e \left (-3 c e (3 a e+10 b d)+8 b^2 e^2+45 c^2 d^2\right )+\frac {\sqrt {c} \left (4 a b e^3-15 a c d e^2+15 c^2 d^3\right )}{\sqrt {a}}\right ) F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{4} \left (2-\frac {b}{\sqrt {a} \sqrt {c}}\right )\right )}{30 c^{11/4} \sqrt {a+b x^2+c x^4}}+\frac {e^2 x \sqrt {a+b x^2+c x^4} (15 c d-4 b e)}{15 c^2}+\frac {e^3 x^3 \sqrt {a+b x^2+c x^4}}{5 c} \]
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Rubi [A] time = 0.42, antiderivative size = 467, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.192, Rules used = {1206, 1679, 1197, 1103, 1195} \[ \frac {e x \sqrt {a+b x^2+c x^4} \left (-3 c e (3 a e+10 b d)+8 b^2 e^2+45 c^2 d^2\right )}{15 c^{5/2} \left (\sqrt {a}+\sqrt {c} x^2\right )}+\frac {\sqrt [4]{a} \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+b x^2+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} \left (e \left (-3 c e (3 a e+10 b d)+8 b^2 e^2+45 c^2 d^2\right )+\frac {\sqrt {c} \left (4 a b e^3-15 a c d e^2+15 c^2 d^3\right )}{\sqrt {a}}\right ) F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{4} \left (2-\frac {b}{\sqrt {a} \sqrt {c}}\right )\right )}{30 c^{11/4} \sqrt {a+b x^2+c x^4}}-\frac {\sqrt [4]{a} e \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+b x^2+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} \left (-3 c e (3 a e+10 b d)+8 b^2 e^2+45 c^2 d^2\right ) E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{4} \left (2-\frac {b}{\sqrt {a} \sqrt {c}}\right )\right )}{15 c^{11/4} \sqrt {a+b x^2+c x^4}}+\frac {e^2 x \sqrt {a+b x^2+c x^4} (15 c d-4 b e)}{15 c^2}+\frac {e^3 x^3 \sqrt {a+b x^2+c x^4}}{5 c} \]
Antiderivative was successfully verified.
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Rule 1103
Rule 1195
Rule 1197
Rule 1206
Rule 1679
Rubi steps
\begin {align*} \int \frac {\left (d+e x^2\right )^3}{\sqrt {a+b x^2+c x^4}} \, dx &=\frac {e^3 x^3 \sqrt {a+b x^2+c x^4}}{5 c}+\frac {\int \frac {5 c d^3+3 e \left (5 c d^2-a e^2\right ) x^2+e^2 (15 c d-4 b e) x^4}{\sqrt {a+b x^2+c x^4}} \, dx}{5 c}\\ &=\frac {e^2 (15 c d-4 b e) x \sqrt {a+b x^2+c x^4}}{15 c^2}+\frac {e^3 x^3 \sqrt {a+b x^2+c x^4}}{5 c}+\frac {\int \frac {15 c^2 d^3-15 a c d e^2+4 a b e^3+e \left (45 c^2 d^2+8 b^2 e^2-3 c e (10 b d+3 a e)\right ) x^2}{\sqrt {a+b x^2+c x^4}} \, dx}{15 c^2}\\ &=\frac {e^2 (15 c d-4 b e) x \sqrt {a+b x^2+c x^4}}{15 c^2}+\frac {e^3 x^3 \sqrt {a+b x^2+c x^4}}{5 c}-\frac {\left (\sqrt {a} e \left (45 c^2 d^2+8 b^2 e^2-3 c e (10 b d+3 a e)\right )\right ) \int \frac {1-\frac {\sqrt {c} x^2}{\sqrt {a}}}{\sqrt {a+b x^2+c x^4}} \, dx}{15 c^{5/2}}+\frac {\left (15 c^2 d^3-15 a c d e^2+4 a b e^3+\frac {\sqrt {a} e \left (45 c^2 d^2+8 b^2 e^2-3 c e (10 b d+3 a e)\right )}{\sqrt {c}}\right ) \int \frac {1}{\sqrt {a+b x^2+c x^4}} \, dx}{15 c^2}\\ &=\frac {e^2 (15 c d-4 b e) x \sqrt {a+b x^2+c x^4}}{15 c^2}+\frac {e^3 x^3 \sqrt {a+b x^2+c x^4}}{5 c}+\frac {e \left (45 c^2 d^2+8 b^2 e^2-3 c e (10 b d+3 a e)\right ) x \sqrt {a+b x^2+c x^4}}{15 c^{5/2} \left (\sqrt {a}+\sqrt {c} x^2\right )}-\frac {\sqrt [4]{a} e \left (45 c^2 d^2+8 b^2 e^2-3 c e (10 b d+3 a e)\right ) \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+b x^2+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{4} \left (2-\frac {b}{\sqrt {a} \sqrt {c}}\right )\right )}{15 c^{11/4} \sqrt {a+b x^2+c x^4}}+\frac {\left (15 c^2 d^3-15 a c d e^2+4 a b e^3+\frac {\sqrt {a} e \left (45 c^2 d^2+8 b^2 e^2-3 c e (10 b d+3 a e)\right )}{\sqrt {c}}\right ) \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+b x^2+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{4} \left (2-\frac {b}{\sqrt {a} \sqrt {c}}\right )\right )}{30 \sqrt [4]{a} c^{9/4} \sqrt {a+b x^2+c x^4}}\\ \end {align*}
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Mathematica [C] time = 2.87, size = 584, normalized size = 1.25 \[ \frac {i e \left (\sqrt {b^2-4 a c}-b\right ) \sqrt {\frac {\sqrt {b^2-4 a c}+b+2 c x^2}{\sqrt {b^2-4 a c}+b}} \sqrt {\frac {-2 \sqrt {b^2-4 a c}+2 b+4 c x^2}{b-\sqrt {b^2-4 a c}}} \left (-3 c e (3 a e+10 b d)+8 b^2 e^2+45 c^2 d^2\right ) E\left (i \sinh ^{-1}\left (\sqrt {2} \sqrt {\frac {c}{b+\sqrt {b^2-4 a c}}} x\right )|\frac {b+\sqrt {b^2-4 a c}}{b-\sqrt {b^2-4 a c}}\right )-i \sqrt {\frac {\sqrt {b^2-4 a c}+b+2 c x^2}{\sqrt {b^2-4 a c}+b}} \sqrt {\frac {-2 \sqrt {b^2-4 a c}+2 b+4 c x^2}{b-\sqrt {b^2-4 a c}}} \left (15 c^2 d e \left (3 d \sqrt {b^2-4 a c}-2 a e-3 b d\right )+c e^2 \left (-30 b d \sqrt {b^2-4 a c}-9 a e \sqrt {b^2-4 a c}+17 a b e+30 b^2 d\right )+8 b^2 e^3 \left (\sqrt {b^2-4 a c}-b\right )+30 c^3 d^3\right ) F\left (i \sinh ^{-1}\left (\sqrt {2} \sqrt {\frac {c}{b+\sqrt {b^2-4 a c}}} x\right )|\frac {b+\sqrt {b^2-4 a c}}{b-\sqrt {b^2-4 a c}}\right )+4 c e^2 x \sqrt {\frac {c}{\sqrt {b^2-4 a c}+b}} \left (a+b x^2+c x^4\right ) \left (3 c \left (5 d+e x^2\right )-4 b e\right )}{60 c^3 \sqrt {\frac {c}{\sqrt {b^2-4 a c}+b}} \sqrt {a+b x^2+c x^4}} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.45, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {e^{3} x^{6} + 3 \, d e^{2} x^{4} + 3 \, d^{2} e x^{2} + d^{3}}{\sqrt {c x^{4} + b x^{2} + a}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (e x^{2} + d\right )}^{3}}{\sqrt {c x^{4} + b x^{2} + a}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.02, size = 1186, normalized size = 2.54 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (e x^{2} + d\right )}^{3}}{\sqrt {c x^{4} + b x^{2} + a}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (e\,x^2+d\right )}^3}{\sqrt {c\,x^4+b\,x^2+a}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (d + e x^{2}\right )^{3}}{\sqrt {a + b x^{2} + c x^{4}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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